Answer:
After 2.80 years the price drops to 300 $
Step-by-step explanation:
Ryan bought a new computer for $2,100.
Price of computer = 2100 $
The value of the computer decreases by 50% each year.
Let p(n) be the price of computer after n years.
[tex]\texttt{Price of computer after 1 year =}2100-\frac{50}{100}\times 2100=0.50^1\times 2100\$\\\\\texttt{Price of computer after 2 years =}0.50^2\times 2100\$\\\\\texttt{Price of computer after 3 years =}0.50^3\times 2100\$\\\\\texttt{Price of computer after n years =}0.50^n\times 2100\$[/tex]
Now we need to find n when price is 300 $.
0.50ⁿ x 2100 = 300
0.50ⁿ = 0.143
n log (0.5) = log 0.143
n x -0.301 = -0.845
n = 2.80
After 2.80 years the price drops to 300 $
