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Which statement is true about the equation fraction 3 over 4z − fraction 1 over 4z + 1 = fraction 2 over 4z + 1?
It has no solution.
It has one solution.
It has two solutions.
It has infinitely many solutions.

Respuesta :

kudzordzifrancis

Answer:

It has no solution.

Step-by-step explanation:

The given equation is

[tex]\frac{3}{4z}-\frac{1}{4z+1}=\frac{2}{4z+1}[/tex]

We multiply through with [tex]4z(4z+1)[/tex]

[tex]4z(4z+1)*\frac{3}{4z}-4z(4z+1)*\frac{1}{4z+1}=4z(4z+1)*\frac{2}{4z+1}[/tex]

[tex]3(4z+1)-4z=8z[/tex]

[tex]12z+3-4z=8z[/tex]

[tex]12z-4z-8z=-3[/tex]

[tex]0=-3[/tex]

This is never true.

Therefore the equation has n solution

aamulka

Answer:

no solution

Step-by-step explanation:

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