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Calculate the molarity of the solution to 3 digits. 100. g of C12H22O11 (molecular weight = 342.28 g/mole) in 1.15 liters of solvent M

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baraltoa

Answer:

0.254 M

Explanation:

The molarity is given by the formula M: Number of Moles/ Vol (L)

Number of Moles : 100 g/342.28 g/mol = 0.292 moles

M: 0.292 moles/ 1.15 L = 0.254 M to three significant figures

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