New volume is 131.428 liters
In the question, we are given;
Initial pressure, P1 = 5.50 atm
Initial volume, V1 = 121 L
Initial temperature, T1 = 293 K
New pressure, P2 = 5.15 atm
New temperature, T2 = 298 K
We are required to find the new volume, V2,
Using the combined gas law, whose formula is ;
[tex]\frac{P1V1}{T1}=\frac{P2V2}{T2}[/tex]
To get V2
[tex]V2=\frac{P1V1T2}{T1P2}[/tex]
Therefore;
[tex]V2=\frac{(5.50)(121)(298)}{(293)(5.15)}[/tex]
[tex]V2=131.428liters[/tex]
Thus, the new volume is 131.428 Liters
