Answer:
0.75 seconds
Explanation:
Given information
Inflow=0.6 cfm
Density of air entering= 0.075 lbm/ft3
Bicycle’s inflated volume= 0.040 ft3
density of air in the inflated tire= 0.4 lbm/ft3
Mass of air pumped=density*volume=0.075*0.04=0.003 lbm
This mass of air pumped is same as mass of air in the inflated tire
Volume of inflated tire=mass/density=0.003/0.4=0.0075 ft3
Time=0.0075/0.6= 0.0125 mins
0.0125*60=0.75 seconds Â