Answer:
10.09 N
Explanation:
Analogously to Newton's second law, torque can be defined as:
[tex]\tau=I\alpha[/tex]
Here, I is the moment of inertia and [tex]\alpha[/tex] is the angular acceleration. We have:
[tex]\tau=(0.65kg*m^2)(29.5\frac{rad}{s^2})\\\tau=19.18N*m[/tex]
Torque is the vector product of the position vector of the point at which the force is applied by the force vector:
[tex]\vec{\tau}=\vec{r}\times \vec{F}[/tex]
Since the effective lever arm is perpendicular to the force, the angle between them is [tex]90^\circ[/tex]. The magnitud of this vector product is defined as:
[tex]\tau=rFsen\theta[/tex].
Solving for F and replacing the known values:
[tex]F=\frac{\tau}{rsen\theta}\\F=\frac{19.18N*m}{1.9m(sen90^\circ)}\\F=10.09N[/tex]
