Answer: 0.2742531
Step-by-step explanation:
Let x denote the random variable that represents the driving times.
As per given we have,
[tex]\mu = 38[/tex]
[tex]\sigma = 5[/tex]
Z-score value corresponds to x= 35,
[tex]z=\dfrac{x-\mu}{\sigma}=\dfrac{35-38}{5}=-0.6[/tex]
Using z-value table ,
The probability that John’s drive to work will take less than 35 minutes:-
P(X<35)=P(z<-0.6)=1-P(z<0.6)=1-0.7257469=0.2742531
hence, the required probability = 0.2742531
