Answer:
147.7 N
221.55 Nm
Explanation:
P = Pressure = 100000 Pa
[tex]R_s[/tex] = Mass-specific gas constant = 287.015 J/kg k
T = Temperature = 10+273 = 283 K
C = Drag coefficient = 1.1
A = Area
r = Radius = 0.2 m
v = Speed of wind = [tex]\frac{150}{3.6}\ m/s[/tex]
L = Length of pole
Density
[tex]\rho=\frac{P}{R_sT}\\\Rightarrow \rho=\frac{100000}{287.058\times 283}\\\Rightarrow \rho=1.2309\ kg/m^3[/tex]
Drag force
[tex]F=\frac{1}{2}\rho CAv^2\\\Rightarrow F=\frac{1}{2}\times 1.2309\times 1.1\times \left(\pi \times 0.2^2\right)\times \left(\frac{150}{3.6}\right)^2\\\Rightarrow F=147.7\ N[/tex]
Force on the circular sign is 147.7 N
[tex]M=F\times L\\\Rightarrow M=147.7\times 1.5\\\Rightarrow M=221.55\ Nm[/tex]
Bending moment at the bottom of the pole is 221.55 Nm
