Answer:
$5
Step-by-step explanation:
Let cost of paperback book be "p"
and
Cost of hardcover book be "h"
Each hardcover is $11 more than each paperback, thus we can write:
h = p + 11
3 paperbacks at "p" each and 4 hardcovers at "h" each totals 79, thus we can write:
3p + 4h = 79
We can now put the 1st equation in 2nd equation and find "p" (cost of paperback book). Shown below:
[tex]3p + 4h = 79\\3p + 4(p+11) = 79\\3p + 4p + 44 = 79\\7p = 79 - 44\\7p = 35\\p = \frac{35}{7}\\p = 5[/tex]
Hence, each paperback book costs $5
