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If 7.0 mol of NO and 5.0 mol of O2 are reacted tegethor. The reaction generates 3.0 mol of NO2. What is the percent yield for the reaction? 2NO(g) + O2(g) -> 2NO2(g)

Respuesta :

Neetoo

Answer:

Percentage yield = 30%

Explanation:

Given data:

Number of moles of NO = 7.0 mol

Number of moles of O₂ = 5 mol

Number of moles of NO₂ = 3 mol

Percentage yield = ?

Solution:

Chemical equation:

2NO + O₂ → 2NO₂

Now we will compare the moles of NO₂ with NO and O₂ .

                  NO           :               NO₂

                  2               :               2

                 7.0             :              7.0

                O₂               :                NO₂

                 1                 :                 2

                 5.0             :               2 ×5.0 = 10 mol

The number of moles of NO₂ produced by NO are less it will be limiting reactant.

Mass of NO₂ = moles × molar mass

Mass of NO₂ = 10 mol × 46g/mol

Mass of NO₂ =  460 g

Actual yield of NO₂:

Mass of NO₂ = moles × molar mass

Mass of NO₂ = 3 mol × 46g/mol

Mass of NO₂ =  138 g

Percentage yield:

Percentage yield = Actual yield/theoretical yield × 100

Percentage yield = 138 g/ 460 g × 100

Percentage yield = 30%

poona2339

Percentage yield is 30%

Percent yield is the percentage ratio of actual yield to the theoretical yield. It is calculated to be the experimental yield divided by the theoretical yield multiplied by 100%. If actual and theoretical yields ​are the same, the percent yield is 100%.

How to calculate theoretical and percent yield?

Use a mass of the product obtained to determine the percent yield: percent yield = grams of the product obtained X 100% theoretical yield (in grams) or convert the mass of product obtained to the moles of products obtained (using the MW of the product) to determine the percent yield: percent yield = moles of the product obtained X 100%

Given data:

Number of moles of NO = 7.0 mol

Number of moles of O₂ = 5 mol

Number of moles of NO₂ = 3 mol

Percentage yield =?

Solution:

Chemical equation:

2NO + O₂ → 2NO₂

Now we will compare the moles of NO₂ with NO and O₂ .

                 NO           :               NO₂

                 2               :               2

                7.0             :              7.0

               O₂               :                NO₂

                1                 :                 2

                5.0             :               2 ×5.0 = 10 mol

If the number of moles of NO₂ produced by NO is less it will be a limiting reactant.

Mass of NO₂ = moles × molar mass

Mass of NO₂ = 10 mol × 46g/mol

Mass of NO₂ =  460 g

Actual yield of NO₂:

Mass of NO₂ = moles × molar mass

Mass of NO₂ = 3 mol × 46g/mol

Mass of NO₂ =  138 g

Percentage yield:

Percentage yield = Actual yield/theoretical yield × 100

Percentage yield = 138 g/ 460 g × 100

Percentage yield = 30%

Learn more about percent yield here https://brainly.com/question/17042787

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