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A world class runner can run long distances at a pace of 15 km/hour. That runner expends 800 kilocalories of energy per hour. a) Find the power (in Watts [W]) the runner is exerting while running. b) Find the total energy (in Joules [J]) exerted by the runner in a 15 km run. c) How many Milky Way (Original Single 52.2g) chocolate bars does the runner need to buy to supply the amount of energy to complete a half-marathon (13.1 miles)? (Cite your source for the number of calories in a Milky Way bar)

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Answer: a) 1.05kW b) 3.78MJ c) 5.3 bars

Explanation :

A)

Conversions give 900 kcal as 900000 x 4.2 J/cal {4.2 J/cal is the standard factor}

= 3780kJ

And 1 hour = 3600s

Therefore, Power in watts = 3780/3600 = 1.05kW = 1050W

B)

At 15km/hour a 15km run takes 1 hour.

1 hour is 3600s and the runner burns 1050 joule per second.

Energy used in 1 hour = 3600 x 1050 J/s

= 3780000 J or 3.78MJ

C)

1 mile = 1.61km so 13.1 mile is 13.1 x 1.61 = 21.1km

15km needs 3.78 MJ of energy therefore 21.1km needs 3.78 x 21.1/15 = 5.32MJ =5320 kJ

Finally,

1 Milky Way = 240000 calories = 4.2 x 240000 J = 1008000J or 1008kJ

This means that the runner needs 5320/1008 = 5.3 bars

The solution to the power, total energy and number of bars are;

933 W, 3,358,800 J, 5 chocolate bars

Calculating Distance, Power and Energy

A) Converting 800 kcal to kJ is 800000 * 4.2 J/cal = 3360kJ

Now, 1 hour = 3600s

Thus;

Power in watts = 3360/3600 = 0.933 kW = 933 W

B) Speed is 15km/hour.

Thus, he achieves a distance of 15km in 1 hour or 3600 s.

1 hour is 3600 s and so energy is;

E = 933 * 3600

E = 3,358,800 J

C) Half marathon is 13.1 mile = 21.1km

15km requires 3,358,800 J of energy.

Thus;

21.1km needs 3358800 * 21.1/15 = 4,724,712 J

Finally,

1 Milky Way Ā = 1008000J

Thus, bars required = 4724712/1008000 ā‰ˆ 5 bars

Read more about distance and energy at; https://brainly.com/question/4931057

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