Answer:
Number of players left after 10 rounds = 64
Step-by-step explanation:
This is an example of geometric progression,
First term = 65,536
[tex]\texttt{Common ratio = }\frac{1}{2}[/tex]
Now we need to term of GP when 10 rounds of play is completed, that is eleventh term of GP.
N th term of GP is given by
[tex]t_n=ar^{n-1}[/tex]
Substituting
[tex]t_{11}=65536\times \left ( \frac{1}{2}\right )^{11-1}\\\\t_{11}=65536\times \left ( \frac{1}{2}\right )^{10}=64[/tex]
Number of players left after 10 rounds = 64