Answer and explanation:
Subtract h + j + 2k = 16 by 4h + 4j + 2k = 5
h + j + 2k = 16
-(4h + 4j + 2k = 5)
-3h - 3j = 11 Then add 3j to both sides to get -3h alone
-3h = 11 + 3j Now divide both sides by -3 to get h
h = [tex]\frac{11 + 3j}{-3}[/tex] = [tex]-\frac{11}{3} - j[/tex]
Plug in h and k to h + j + 2k = 16 ---> [tex]-\frac{11}{3} - j[/tex] + j + 2(1) = 16
Then add any like terms together [tex]-\frac{11}{3} + \frac{6}{3}[/tex] + 2j = 16
Add [tex]-\frac{5}{3}[/tex] on both sides 2j = [tex]\frac{5}{3}[/tex] + 16
Divide both sides by 2 [tex]\frac{2j}{2} = \frac{\frac{5}{3}}{2}[/tex]
You can divide a fraction by a fraction, so you do kcf j = [tex]\frac{5}{3}[/tex] · [tex]\frac{2}{1}[/tex] = [tex]\frac{10}{3}[/tex]
Multiply h + j + 2k = 16 by 2 ---> 2h + 2j + 4k = 32
Then subtract 2h + 2j + 4k = 32 by 2h + 2j + k = 31
2h + 2j + 4k = 32
-(2h + 2j + k = 31)
3k = 1 Divide both sides by 3 to get k
k = 1
