A copper wire has a circular cross section with a radius of 1.50 mm. (a) If the wire carries a current of 2.60 A, find the drift speed of the electrons in the wire. (Assume the density of charge carriers (electrons) in a copper wire is n = 8.46 1028 electrons/m3.) m/s (b) All other things being equal, what happens to the drift speed in wires made of metal having a larger number of conduction electrons per atom than copper? Explain.

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aristocles aristocles · Answer 1 · 2019-10-24T05:41:15+02:00

Answer:

Part a)

[tex]v_d = 2.72 \times 10^{-5} m/s[/tex]

Part b)

it is inversely depends on the number density so on increasing the number density the drift speed will decrease

Explanation:

Part a)

As we know that the cross-sectional radius is

[tex]r = 1.50 mm[/tex]

now we will have

[tex]A = \pi r^2[/tex]

[tex]A = \pi(1.50 \times 10^{-3})^2[/tex]

[tex]A = 7.07 \times 10^{-6} m^2[/tex]

now we know that

[tex]i = neA v_d[/tex]

so we will plug in all data

[tex]2.60 = (8.46 \times 10^{28})(1.6 \times 10^{-19})(7.07\times 10^{-6})v_d[/tex]

[tex]v_d = 2.72 \times 10^{-5} m/s[/tex]

Part b)

As we know that

[tex]i = neAv_d[/tex]

now if all other things are same

[tex]v_d = \frac{i}{neA}[/tex]

since it is inversely depends on the number density so on increasing the number density the drift speed will decrease