Answer: 4/16 yellow Labradors, 9/16 black Labradors and 3/16 brown Labradors.
Explanation: Two dihybrids would have BbEe alleles. Using Mendel's chess table of independent segregation to show the offspring, we have the following results:
BBee - 1/16 - yellow
BBEe - 2/16 - black
BBEE - 1/16 - black
BbEe - 4/16 - black
Bbee - 2/16 - yellow
BbEE - 2/16 - black
bbEe - 2/16 - brown
bbEE - 1/16 - brown
bbee - 1/16 - yellow
If the offspring presents B_E_ phenotypes, it will have black pigment deposition. If the offspring presents bbE_ phenotypes, it will have brown pigment deposition. Otherwise, if it presents _ _ee phenotypes, there won't be any pigment deposition, therefore they are yellow.
Adding up all the phenotypes ratios, we have 4/16 yellow Labradors, 9/16 black Labradors and 3/16 brown Labradors.