The slope intercept form of the line passing through the given points (3, -2) and (0, 4) is y = -2x + 4
Given the following points:
- Points on the x-axis = (3, -2)
- Points on the y-axis = (0, 4)
To find the slope intercept form of the line passing through the given points (3, -2) and (0, 4):
The slope of a line refers to the gradient of a line and it is typically used to describe both the direction and steepness of an equation of a straight line.
Mathematically, the slope of a line is given by the following formula;
[tex]Slope. \;m = \frac{Change \; in \; y \;axis}{Change \; in \; x \;axis} \\\\Slope. \;m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
Substituting the given points into the formula, we have;
[tex]Slope. \;m = \frac{4 \;- \;[-2]}{0\; - \;3}\\\\Slope. \;m = \frac{6}{-3}[/tex]
[tex]y = mx+b\\\\-2 = -2(3) +b\\\\-2=-6+b\\\\b=6-2[/tex]
b = 4
y = -2x + 4
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