Answer:
T₂ = 180.4 K
Explanation:
According to general gas equation:
P₁V₁/T₁ = P₂V₂/T₂
Given data:
Initial volume = 350 mL
Initial pressure = 1.20 atm
Initial temperature = 30 °C (30 +273 = 303 K)
Final volume = 250 mL
Final pressure = 1 atm
Final temperature = ?
Solution:
P₁V₁/T₁ = P₂V₂/T₂
T₂ = P₂V₂ T₁ /P₁V₁
T₂ = 1 atm × 250 mL × 303 K / 1.20 atm × 350 mL
T₂ = 75750 atm .mL. K / 420 atm. mL
T₂ = 180.4 K
180.4 K temperature would be needed for the same amount of gas to fit into a 250 mL flask at standard pressure.
Ideal gas equation for the calculation of temperature will be represented as:
P₁V₁/T₁ = P₂V₂/T₂, where
P₁ = Initial pressure = 1.20 atm
V₁ = Initial volume = 350 mL
T₁ = Initial temperature = 30 °C = 30 +273 = 303 K
P₂ = Final pressure = 1 atm
V₂ = Final volume = 250 mL
T₂ = Final temperature = to find?
On putting all these values on the above equation and calculating for T₂ as:
T₂ = 1 atm × 250 mL × 303 K / 1.20 atm × 350 mL = 180.4 K
Hence, 180.4 K is the needed temperature.
To know more about ideal gas equation, visit the below link:
https://brainly.com/question/25290815
