Respuesta :
Answer:
0.95 atm
Explanation:
We are given;
Initial pressure, P1 = 1.0 atm
Initial temperature, T1 =298 K (25°C + 273)
Initial volume, V1 = 0.985 L
Final temperature, T2 = 295 K (22°C + 273)
Final volume, V2 = 1.030 L
We are required to find final air pressure;
Using the combined gas law;
[tex]\frac{P1V1}{T1} =\frac{P2V2}{T2}[/tex]
To get, P2 ;
[tex]P2=\frac{P1V1T2}{T1V2}[/tex]
[tex]P2=\frac{(1.0)(0.985L)(295)}{(1.030)(298)}[/tex]
[tex]P2 = 0.947 atm[/tex]
= 0.95 atm
Therefore, the air pressure at the top of the mountain is 0.95 atm