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The average speed of a nitrogen molecule in air is about 6.70 ✕ 102 m/s, and its mass is about 4.68 ✕ 10-26 kg. (a) If it takes 4.20 ✕ 10-13 s for a nitrogen molecule to hit a wall and rebound with the same speed but moving in an opposite direction (assumed to be the negative direction), what is the average acceleration of the molecule during this time interval? m/s2 (b) What average force does the molecule exert on the wall? N

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usmanbiu

Answer:

acceleration = -3.1163 x 10^15 m/s^2

force = -1.4584 x 10^-10 N

Explanation:

from the question we were given the following;

velocity= 6.70 ✕ 102 m/s

mass= 4.68 ✕ 10-26 kg

time = 4.20 ✕ 10-13 s

  • acceleration = change in velocity (v₂- v₁)/ time

      v₂ in this case is  -6.70 ✕ 102 m/s because the nitrogen rebounded with the same velocity but in the opposite direction while v₁ remains 6.70 ✕ 102 m/s

 acceleration = ( -6.70 ✕ 102  -6.70 ✕ 102) / 4.20 ✕ 10-13

   = -3.1163 x 10^15 m/s^2

  • the average force can be determined using Force = mass x acceleration

    force = 4.68 ✕ 10-26 x 3.1163 x 10^15

       =-1.4584 x 10^-10 N

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