Respuesta :
Answer:
Step-by-step explanation:
In this case, we can put all the scenarios and then, count the scenario which can be rainy at least one day (it doesn't matter if it's day 1, day 2 or day 3 because it's asking for exactly one day). With this, we can also assume that the rest of the days will be sunny so:
We have this scenarios:
S: Sunny
R: Rainy
Now, let's do the scenarios:
If day 1 begins sunny:
SSS, SSR, SRS, SRR
If day 1 begins with Rain:
RRR, RRS, RSR, RSS
So, we have 8 possible scenarios, now let's see which ones we have one day of raining and the rest of the days, are sunny.
SSR, SRS and RSS
We have 3 scenarios, which can be rainy exactly one day.
So the probability is:
3/8 = 0.375 or simply 37.5%
Using the binomial probability relation, the probability that it rains on exactly one day is 0.375
Let :
- Sunny = S
- Rainy = R
The probability that it rains on exactly one day can be obtained using the binomial probability relation :
- P(x = x) = nCx * p^x * q^(n-x)
- Probability of success = p = 0.5
- n = number of trials = 3
- q = 1 - p = 0.5
P(x = 3) = 3C1 * 0.5¹ * 0.5²
P(x = 1) = 3 × 0.5 × 0.25
P(x = 1) = 0.375
Therefore, the probability that it rains on exactly one day is 0.375
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