Respuesta :
Answer: The amount of oxygen gas consumed by mouse is 0.202 grams.
Explanation:
We are given:
Initial pressure of air = 769.0 torr
Final pressure of air = 717.1 torr
Pressure of oxygen = Pressure decreased = Initial pressure - Final pressure = (769.0 - 717.1) torr = 51.9 torr
To calculate the amount of oxygen gas consumed, we use the equation given by ideal gas which follows:
[tex]PV=nRT[/tex]
where,
P = pressure of the gas = 51.9 torr
V = Volume of the gas = 2.20 L
T = Temperature of the gas = 292 K
R = Gas constant = [tex]62.364\text{ L. Torr }mol^{-1}K^{-1}[/tex]
n = number of moles of oxygen gas = ?
Putting values in above equation, we get:
[tex]51.9torr\times 2.20L=n\times 62.364\text{ L. Torr }mol^{-1}K^{-1}\times 292K\\\\n=\frac{51.9\times 2.20}{62.364\times 292}=0.0063mol[/tex]
To calculate the mass from given number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
Moles of oxygen gas = 0.0063 moles
Molar mass of oxygen gas = 32 g/mol
Putting values in above equation, we get:
[tex]0.0063mol=\frac{\text{Mass of oxygen gas}}{32g/mol}\\\\\text{Mass of oxygen gas}=(0.0063mol\times 32g/mol)=0.202g[/tex]
Hence, the amount of oxygen gas consumed by mouse is 0.202 grams.
