The decomposition of dinitrogen pentoxide, N2O5, to NO2 and O2 is a first-order reaction. At 60°C, the rate constant is 2.8 × 10-3min-1. If a rigid vessel initially contains only N2O5 at a pressure of 125 kPa, how long will it take for the total pressure to reach 176 kPa?options (pick 1)a)113 minb)129 minc)42 mind)182 mine)62 minf)83 min

Respuesta :

The time required by [tex]\rm N_2O_5[/tex] to reach the total pressure of 176 kPa has been 113 minutes. Thus, option A is correct.

For the decomposition of Nitrogen pentaoxide, the ICE table for the balanced chemical equation will be:

2 [tex]\rm N_2O_5[/tex] [tex]\rightarrow[/tex] 4 [tex]\rm NO_2[/tex] + [tex]\rm O_2[/tex]

I     2x          0         0

C     -2x      +4x       +x

E    -2x       +4x       +x

Total pressure has been the partial pressure of each gas.

Final pressure = Initial pressure -2x + 4x + x

176 kPa = 125 kPa -3x

3x = 51

x = 17

The pressure of [tex]\rm N_2O_5[/tex] = 125 kPa.

After the completion of reaction the pressure has been reduced by 2x.

Final pressure of [tex]\rm N_2O_5[/tex] = 125 - 2x

= 125 - 2(17)

= 125 - 34

= 91 kPa.

The initial pressure [tex]\rm N_2O_5[/tex] = 125 kPa

The time can be given by:

t = [tex]\rm \dfrac{2.303}{Rate\;constant}\;\times\;log\;\dfrac{Initial\;pressure}{Final\;pressure}[/tex]

t = [tex]\rm \dfrac{2.303}{2.8\;\times\;10^-^3}\;\times\;log\;\dfrac{125}{91}[/tex]

t = 113.3963 minutes

t = 113.4 minutes.

The time required by [tex]\rm N_2O_5[/tex] to reach the total pressure of 176 kPa has been 113 minutes. Thus, option A is correct.

For more information about the decomposition reaction, refer to the link:

https://brainly.com/question/24936069