Answer:
F= 67.5 N
Explanation:
We use the equation for the Coulomb's Law of Force between two charges Q1 and Q2 (in Coulombs) separated by a distance d (in meters):
[tex]F=k\frac{Q1*Q2}{d^2}[/tex]
where the constant k is the Coulomb's constant ([tex]9*10^9 N\frac{m^2}{C^2}[/tex]
The charges are [tex]Q1=3.0*10^{-6}C[/tex], Q2=2.5*10^{-7}C; the distance we convert into meters to match the appropriate units of the Coulomb constant k (1 cm = 0.01 m)
Now we input all these data into the equation, knowing that given the appropriate units, the force will be expressed in Newtons (N):
[tex]F=k\frac{Q1*Q2}{d^2}\\F=9*10^9\frac{3.0*10^{-6}*2.5*10^{-7}}{0.01^2} N\\F= 67.5N[/tex]
