Answer:
13.5 s
Explanation:
An object is dropped from a tower 828 m high. We want to find how long it takes to hit the ground.
The motion of the object is a free fall motion, so we can use the following suvat equation:
[tex]s=ut+\frac{1}{2}at^2[/tex]
where, taking downward as positive direction:
s = 828 m is the distance covered by the object in its fall
u = 0 is the initial vertical velocity of the object
[tex]a=g=9.8 m/s^2[/tex] is the acceleration of gravity
t is the time taken for the fall
Substituting the numbers and solving for t, we find:
[tex]t=\sqrt{\frac{2s}{a}}=\sqrt{\frac{2(828)}{9.8}}=13.5 s[/tex]
