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It is well known that bullets and other missiles fired at Superman simply bounce off his chest. Suppose that a gangster sprays Superman's chest with 6.7 g bullets at the rate of 78 bullets/min, and the speed of each bullet is 530 m/s. Suppose too that the bullets rebound straight back with no change in speed. What is the magnitude of the average force on Superman's chest from the stream of bullets?

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umohduke14

Answer: 9.2 N

Explanation:

Δt= 1min/78 = 60/78 = 0.77s


FΔt=Δp= mΔv= m[v-(-v)] =2mv


F=2mv/Δt

= 2 x 0.0067x 530/0.77 = 0.0134 x 688.31 = 9.2 N

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