Ammonium carbonate will form 3 moles of ions.
Methyl alcohol will form 0 moles of ions.
Methane will form 0 moles of ions.
Aluminum sulfite will form 3 moles of ions.
Hydrobromic acid will form 2 moles of ions.
Explanation:
One mole of ammonium carbonate will form 3 moles of ions when dissolved in water.
(NH₄)₂CO₃ (s) + H₂O (l) → 2 NH₄⁺ (aq) + CO₃²⁻ (aq) + H₂O (l)
One mole of methyl alcohol will form 0 moles of ions when dissolved in water.
(actually it form ions because of its acidic behavior but they are at the order of 10⁻⁷ moles, however in the framework of this question we may say that there are none)
One mole of methane will form 0 moles of ions when dissolved in water.
Methane does not react with water (in normal conditions) so will not form ions.
One mole of aluminum sulfite will form 3 moles of ions when dissolved in water.
Al₂SO₃ (s) + H₂O (l) → 2 Al₃⁺ (aq) + SO₃²⁻ (aq) + H₂O (l)
One mole of hydrobromic acid will form 2 moles of ions when dissolved in water.
HBr (l) + H₂O (l) → Br⁻ (aq) + H₃O⁺ (aq)
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solvation of ions
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Some substances dissolve in water to yield ions. Molecular substances do not yield ions in solution.
Some substances dissolve in water to yield ions. Solutions of these substances serve as electrolytes. substances such as HBr, (NH4)2CO3, and Al2(SO3)3 all yield ions in solution.
For ammonium carbonate, its dissolution in water occurs as follows;
(NH4)2CO3(s) ⇄ 2NH4^+(aq) + CO3^2-(aq)
Hence three moles of ions are formed when (NH4)2CO3 dissolves in water.
For methyl alcohol and methane, 0 moles of ions will be formed because the compound is molecular and does not form ions.
For aluminum sulfite, its dissolution in water occurs as follows;
Al2(SO3)3(s) ⇄ 2Al^3+(aq) + 3SO3^2-(aq)
We can see that five moles of ions are formed when Al2(SO3)3 is dissolved in water.
For hydrobromic acid, the compound dissolves in water as shown below;
HBr(s) ⇄ H^+(aq) + Br^-(aq)
We can see that two moles of ions are formed when HBr is dissolved in water.
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