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a gas container is initially at 47 mm Hg and 77 K (liquid nitrogen temperature.) what will the pressure be when the container warms up to room temperature of 25 C?

Respuesta :

nkirotedoreen46

Answer:

181.90 mmHg

Explanation:

  • According to pressure law, the pressure of a gas and its absolute temperature are directly proportional at a constant volume.
  • Mathematically, [tex]P\alpha T[/tex]
  • Thus; [tex]P=kT[/tex]
  • Therefore, at varying temperature and pressure;

[tex]\frac{P1}{T1}=\frac{P2}{T2}[/tex]

In this case, we are given;

Initial temperature, T1 = 77 K

Initial pressure, P1 = 47 mmHg

Final temperature, T2 = 25 °C + 273

                                     = 298 K

We are required to find the final pressure;

Using pressure law;

P2 = (P1/T1)T2

    = (47/77K) × 298 K

    = 181.90 mmHg

Therefore, the new pressure will be 181.90 mmHg