Respuesta :
Answer:
The final pressure of the whole system is 2.849 atm
Explanation:
According to Boyle's law, for eacht gas applies the following equation:
PiVi = PfVf   or Pf = PiVi/Vf
with Pi = the initial pressure
with Vi = the initial volume
with Pf = the final pressure
with Vf = the final volume
The final volume for each gas is (47.0 + 30.0 + 250 + 21.0) mL, which is in total = 348 mL
2. For the first bulb, with argon:
Pf = (4.49 atm)(30.0 mL) / (348 mL)
= 0.387 atm
For the second bulb, with neon
Pf = (2.64 atm)(250 mL) / (348 mL)
= 1.897 atm
For the third bulb, with hydrogen:
Pf = (9.36 atm)(21 mL) / (348 mL)
= 0.565 atm
Step 3:Calculate the final pressure
P total = P (Ar) + P (Ne) + P (H2)
= (0.387 + 1.897 + 0.565) atm
= 2.849 atm
The final pressure of the whole system is 2.849 atm
The final pressure of the whole system is 2.849 atm.
What is the pressure?
The rate of a reaction involving reacting gases is increased by increasing the pressure on the reaction.
Given, Pi- the initial pressure
Vi – the initial volume
Pf – the final pressure
Vf - the final volume
Final volume  = (47.0 + 30.0 + 250 + 21.0)
Pf = 348 ml
Step 1: Now, from Boyle's law
PiVi = PfVf Â
Pf = PiVi/Vf
(a) The first bulb with argon:
[tex]\bold{Pf = \dfrac{(4.49 atm) (30.0 mL)}{(348 mL)}= 0.387 atm }[/tex]
(b) The second bulb with neon:
[tex]\bold{Pf = \dfrac{(2.64 atm) (250 mL)}{(348 mL)}= 1.897 atm }[/tex]
(c) the third bulb with hydrogen:
[tex]\bold{Pf = \dfrac{(9.36 atm) (21 mL)}{(348 mL)}= 0.565\;atm }[/tex]
Step 2: Calculating the final pressure
Final pressure = P (Ar) + P (Ne) + P (Hâ‚‚)
= (0.387 + 1.897 + 0.565) atm
= 2.849 atm
Thus, The final pressure of the whole system is 2.849 atm.
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