Answer:
The amount of heat required to raise the temperature of the sample from 298 to 385 Kelvin, is 16.6 kJ
Explanation:
Step 1: Given data
A 79.0 g sample of ethanol raises from 298 K to 385 K
The specific heat of ethanol is 2.42J/g°C
Step 2: Calculate the heat transfer
Q = m*Cp*ΔT
with m = the mass of the ethanol sample (in grams)
⇒ mass = 79 grams
with Cp = the specific heat capacity of ethanol (in J/g°C)
⇒ Cp = 2.42 J/g°C
with ΔT = the change of temperature (T2-T1)
⇒ ΔT = 385 K - 298K = 112 °C - 25 °C = 87
Q = 79 grams * 2.42 J/g°C * 87 = 16632.66 j = 16.6 kJ
The amount of heat required to raise the temperature of the sample from 298 to 385 Kelvin, is 16.6 kJ
