Answer:
F = 53,440 N (890,67 N each officer)
Explanation:
So, in this problem, I will assume you are asking to estimate the force which the officer pull the airplane right?
If that's correct, here's the way you could do it.
Using the second law of Newton, we know that:
F = m*a
However we have a friction coefficient, so we also have a friction force, therefore:
F - Ff = m*a
Solving for F:
F = m*a + Ff
Now Ff, it's calculated this way:
Ff = μr*m*g
Where g: gravity acceleration = 9.8 m/s^2
Let's calculate first the Ff:
Ff = 0.02 * 200,000 * 9.8 = 39,200 N
Now, let's calculate the acceleration a:
If x = at^2/2 ---> then a = 2d/t^2
solving for a:
a = 2 * 100 / 53^2 = 0.0712 m/s^2
We have the mass, acceleration, friction force, let's calculate the total force:
F = 200,000 * 0.0712 + 39,200
F = 14,240 + 39,200
F = 53,440 N
This would be the total force of all the officers, so, if you want the force that each office apply it would be:
F = 53,440 / 60 = 890,67 N