Answer:
V₂ = 9.14 L
Explanation:
Given data:
Initial volume = 4.28 L
Initial pressure = 42.20 mmHg (42.20/760 = 0.056 atm)
Initial temperature = 10.24 °C (72 +273 = 283.24 K)
Final temperature = 213°C (213+273 = 486 K)
Final pressure = 4.56 KPa (4.56/101.325 = 0.045 atm)
Final volume = ?
Solution:
P₁V₁/T₁ = P₂V₂/T₂
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 0.056 atm × 4.28 L × 486 K / 283.24 K × 0.045 atm
V₂ = 116.48 atm .L. K / 12.75 K . atm
V₂ = 9.14 L
