Answer:
[tex]KE=3566.706J/mol\\v_{rms,CO}=504.74m/s\\v_{rms,CO_2}=402.65m/s\\v_{rms,SO_3}=298.61m/s[/tex]
Explanation:
Hello,
Kinetic energy is computed for all the gases as follows, since it does not depend on a particular property of the gas:
[tex]KE=\frac{3}{2} RT=\frac{3}{2} *8.314*\frac{J}{mol*K} *286K=3566.706J/mol[/tex]
On the other hand, root mean square velocities for each compound depend on their molecular mass and are computed as follows:
[tex]v_{rms,i}=\sqrt{\frac{3RT}{M} } \\v_{rms,CO}=\sqrt{\frac{3*8.314\frac{J}{mol*K} *286K}{0.028kg/mol} } =504.74m/s\\v_{rms,CO_2}=\sqrt{\frac{3*8.314\frac{J}{mol*K} *286K}{0.044kg/mol} } =402.65m/s\\v_{rms,SO_3}=\sqrt{\frac{3*8.314\frac{J}{mol*K} *286K}{0.080kg/mol} } =298.61m/s[/tex]
Best regards.
