a)
The given quantities are:
[tex]d = 10.0 m[/tex] is the vertical distance covered by the ball
[tex]t=0.88 s[/tex] is the time it takes for the ball to reach the ground
[tex]v_0 = 0[/tex] is the initial velocity of the ball
[tex]a=g[/tex] is the acceleration of gravity
[tex]v[/tex] is the final velocity of the ball
b) [tex]25.82 m/s^2[/tex]
In order to find the acceleration of gravity, we use the following equation:
[tex]d=v_0 t + \frac{1}{2}at^2[/tex]
Where
[tex]v_0 =0[/tex]
t = 0.88 s
d = 10.0 m
Solving for a,
[tex]a=\frac{2d}{t}=\frac{2(10.0)}{0.88^2}=25.82 m/s^2[/tex]
c) Jupiter
The value which is closer to the value calculated is the value for Jupiter, which is 25.95, so the planet must be Jupiter.
d) 22.7 m/s
We can find the final velocity of the ball before striking the ground by using the equation
[tex]v_f^2 = v_0^2 +2ad[/tex]
where
[tex]v_0 =0[/tex]
[tex]a=25.82 m/s^2[/tex]
d = 10.0 m
Solving for v,
[tex]v=\sqrt{v_0^2+2ad}=\sqrt{0+2(25.82)(10.0)}=22.7 m/s[/tex]
