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An 11.0-W energy-efficient fluorescent lightbulb is designed to produce the same illumination as a conventional 40.0-W incandescent lightbulb. Assuming a cost of $0.111/kWh for energy from the electric company, how much money does the user of the energy-efficient bulb save during 220 h of use?

Respuesta :

Answer:

[tex]Savings = $0.709[/tex]

Explanation:

Energy consumed by 11 W energy efficient fluorescent bulb is given as

[tex]E = Power \times time[/tex]

now we can say

[tex]E = 11 \times 220h[/tex]

[tex]E = 2.42 kWh[/tex]

now total cost of the energy used is given as

[tex]Amount = 2.42 \times $0.111[/tex]

[tex]Amount = $0.268[/tex]

Now for conventional 40 W bulb  we can say

[tex]E = Power \times time[/tex]

now we can say

[tex]E = 40.0 \times 220h[/tex]

[tex]E = 8.8 kWh[/tex]

now total cost of the energy used is given as

[tex]Amount = 8.8 \times $0.111[/tex]

[tex]Amount = $0.977[/tex]

So total money saving is given as

[tex]Savings = $0.977 - $0.268[/tex]

[tex]Savings = $0.709[/tex]

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