PCl₅ mass = 69.3054 g
The reaction equation is the chemical formula of reactants and products
A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reactants and products
Reaction
P₄ + 10 Cl₂ → 4 PCl₅
We look for moles of each reactant so we can determine the limiting of the reactants
mass 28.0 g
molar mass: 123.9
mole = mass : molar mass
mole = 28 : 123.9
mole: 0.2260
mass 59 g
molar mass: 71
mole = mass : molar mass
mole = 59 : 71
mole: 0.8310
From the coefficient of the equation above, it shows that the ratio of mol P₄: mol Cl₂ = 1:10
A method that can be used to find limiting reactants is to divide the number of moles of known substances by their respective coefficients, and small or exhausted reactans become a limiting reactants
ratio P₄: 0.2260: 1 = 0.2260
ratio Cl₂: 0.8310: 10 = 0.08310
Because Cl₂ ratio smaller then Cl₂ becomes the limiting reactants
So mole PCl₅ is based on mole Cl₂
From the coefficient of reaction: mol PCl₅: mol Cl₂ = 4: 10
then mole PCl₅ = 4/10 x 0.8310 = 0.3324
molar mass PCl₅= 208.5
mass PCl₅ = mole x molar mass
PCl₅ mass = 0.3324 x 208.5
PCl₅ mass = 69.3054 g
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We have that from the Question, it can be said that mass of PCl5 will be produced from the given masses of both reactants
From the Question we are told
What mass of [tex]PCl_5[/tex] will be produced from the given masses of both reactants? 28.0 g of P4 and 59.0 g of Cl2
Generally the equation for reaction is mathematically given as
[tex]P_4+10Cl_2------4PCl_5[/tex]
Therefore
No of moles P_4=[tex]\frac{28}{124}[/tex]
No of moles P_4=0.225moles
No of moles of Cl_2=[tex]\frac{59}{71}[/tex]
No of moles of Cl_2=0.831 moles
0.831 mole of Cl_2=0.0.831 moles of P4 and produce 0.3324 moles PCl_5
Therefore
[tex]Mass\ a\ PCl_5 =moles\ of\ PCl_5 *molar\ mass\ PCl_5\\\\Mass\ a\ PCl_5 =0.3324+208[/tex]
[tex]Mass a PCl_5 =69g[/tex]
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