Respuesta :
Answer:
0.42 is closest to the proportion of customer purchase amounts between $14.00 and $16.00
Step-by-step explanation:
Mean = [tex]\mu = 15.50[/tex]
Standard deviation = [tex]\sigma = 1.72[/tex]
We are supposed to find the proportion of customer purchase amounts between $14.00 and $16.00
P(14<x<16)
Formula : [tex]z=\frac{x-\mu}{\sigma}[/tex]
At x = 14
[tex]z=\frac{14-15.50}{1.72}[/tex]
[tex]z=-0.8720[/tex]
Refer the  z table for p value
P(x<14)=0.1922
At x = 16
[tex]z=\frac{16-15.50}{1.72}[/tex]
[tex]z=0.290[/tex]
Refer the  z table for p value
P(x<16)=0.6141
P(14<x<16)=P(x<16)-P(x<14)=0.6141-0.1922=0.42
So, Option C is true
Hence 0.42 is closest to the proportion of customer purchase amounts between $14.00 and $16.00
Answer:
C
Step-by-step explanation:
Find the z-scores for both $14 and $16, then find the area that is between both of the values which should be 0.42