Answer:
[tex]\frac{dQ}{dt} = 351.07 Watt[/tex]
Explanation:
As we know that heat transfer is given as
[tex]\frac{dQ}{dt} = \sigma e A (T^4 - T_s^4)[/tex]
so we will have
[tex]\sigma = 5.67 \times 10^{-8}[/tex]
[tex]e = 0.90[/tex]
[tex]A = 1 m^2[/tex]
[tex]T = (273 + 15) = 288 K[/tex]
[tex]T_s = 2.7 K[/tex]
now we will have
[tex]\frac{dQ}{dt} = (5.67 \times 10^{-8})(0.90)(1)(288^4 - 2.7^4)[/tex]
[tex]\frac{dQ}{dt} = 351.07 Watt[/tex]
