Answer:
Option A [tex]sin(A)=\frac{9}{15}[/tex]
Step-by-step explanation:
we know that
[tex]tan(A)=sin(A)/cos(A)[/tex]
Solve for sin(A)
[tex]sin(A)=tan(A)cos(A)[/tex]
we have
[tex]tan(A)=\frac{9}{12}[/tex]
[tex]cos(A)=\frac{12}{15}[/tex]
substitute
[tex]sin(A)=\frac{9}{12}(\frac{12}{15})[/tex]
[tex]sin(A)=\frac{9}{15}[/tex]