Respuesta :
Answer:
The answer to your question is: Molecular formula = C₁₈H₂₄O₂
Explanation:
Estradiol
C = 79.37 %
H = 8.88 %
O = 11.75 %
Molar mass = 272.37
Process
Carbon = 79.37 g
Hydrogen = 8.88 g
Oxygen = 11.75 g
12 g of Carbon ----------------- 1 mol
79.37 g ---------------- x
x = (79.37 x 1) / 12
x = 6.61 mol
1 g of Hydrogen ---------------- 1 mol
8.88 g ---------------- x
x = (8.88 x 1 ) / 1
x = 8.88 mol
16 g of Oxygen ------------------ 1 mol
11.75 g ----------------- x
x = (11.75 x 1) / 16
x = 0.73
Divide by the lowest number of moles
Carbon = 6.61 / 0.72 = 9.2
Hydrogen = 8.88 / 0.73 = 12.2
Oxygen = 0.73/0.73 = 1
Empirical formula
C₉H₁₂O₁
MW of the empirical formula = (12 x 9) + (12 x 1) + (16 x 1)
= 136 g
Divide molar mass of estradiol by the molar mass of the empirical formula.
= 272 / 136
= 2
Then the molecular formula is:
2(C₉H₁₂O) = C₁₈H₂₄O₂