Answer:
[tex]r_{cm} = 0.074 m[/tex] from the position of the center of the Sun
Explanation:
As we know that mass of Sun and Jupiter is given as
[tex]M_s = 1.98 \times 10^{30} kg[/tex]
[tex]M_j = 1.89 \times 10^{27} kg[/tex]
distance between Sun and Jupiter is given as
[tex]r = 7.78 \times 10^{11} m[/tex]
now let the position of Sun is origin and position of Jupiter is given at the position same as the distance between them
so we will have
[tex]r_{cm} = \frac{M_s r_1 + M_j r_2}{M_s + M_j}[/tex]
[tex]r_{cm} = \frac{1.98 \times 10^{30} (0) + (1.89 \times 10^{27})(7.78 \times 10^{11})}{1.98 \times 10^{30} + 1.89 \times 10^{27}}[/tex]
[tex]r_{cm} = 0.074 m[/tex] from the position of the center of the Sun
