Given the following reactions

N2 (g) + O2 (g) → 2NO (g) ΔH = +180.7 kJ

2N2O (g) → O2 (g) + 2N2 (g) ΔH = -163.2 kJ

the enthalpy of reaction for

2N2O (g) → 2NO (g) + N2 (g)

is ________ kJ.

Respuesta :

Answer:

17.5 kJ

Explanation:

N2 (g) + O2 (g) → 2NO (g) ΔH = +180.7 kJ

2N2O (g) → O2 (g) + 2N2 (g) ΔH = -163.2 kJ

On Adding the two reactions,

+180.7

-163.2

_______

17.5 kJ

2N2O (g) → 2NO (g) + N2 (g)

is 17.5 kJ