Answer:
#a. ⁵¹₂₂Ti + ⁰₋₁e → ⁵¹₂₃V
#b. 0.0977 g
Solution and explanation:
#a.
- Titanium-51 is the radioisotope that undergoes Beta emission to emit a daughter isotope Vanadium-51 (Mass number-51 and atomic number -23).
- Titanium-51 has a mass number of 51 and atomic number of 22.
- A beta particle is equivalent to ⁻¹₀e
- Beta emission does not affect the mass number of an isotope but increases the atomic number by 1.
Therefore;
The reaction will be;
⁵¹₂₂Ti + ⁻¹₀e → ⁵²₂₂V
#b.
The half life of Ti-51 is 6 minutes
We can calculate the mass remaining after 1 hour (60 min)
Original mass of the sample = 10.0 g
But; using the formula;
Remaining mass = Original mass × (1/2)^n , where n is the number of half lives.
in this case, n = time/half life
= 60 min ÷ 6 min
= 10
Therefore;
Remaining mass = 100 g × (1/2)^10
= 0.0977 g
Therefore, the mass of Ti-51 remaining after 1 hour will be 0.0977 g
