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A shopper pushes a cart 29 m south down one aisle and then turns 90.0° west and moves 29 m. He then makes another 90.0° turn and moves 14 m. (a) What is the largest possible displacement of the shopper?

Respuesta :

Answer:

[tex]d = 51.86 m[/tex]

Explanation:

For largest possible displacement we can say that it must move towards south after it turns 90 degree at the end

So we will have

[tex]x_1 = 29 m[/tex] South

[tex]y_1 = 29 m[/tex] West

[tex]x_2 = 14 m[/tex] South

so total displacement towards South

[tex]x = x_1 + x_2 = 29 + 14[/tex]

[tex]x = 43 m[/tex]

so net maximum displacement will be

[tex]d = \sqrt{x^2 + y^2}[/tex]

[tex]d = \sqrt{43^2 + 29^2}[/tex]

[tex]d = 51.86 m[/tex]

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