Vince went on a 3 day hiking trip. Each day, he walked 3/4 the distance that he walked the day before. He walked 83.25 kilometers total in the trip. How far did Vince walk on the 1st day of the trip?

Respuesta :

Answer:

36 km.

Step-by-step explanation:

Suppose  he walked n km on the first day .

We create the following equation

n + 3/4 n + (3/4)^2 n = 83.25

n + 0.75n + 0.5625n = 83.25

2.3125n = 83.25

n = 36 km.

Distance cover by Vince in 1st day is 36 km

Given that;

Total distance = 83.25 km

Number of days walking = 3

Find:

Distance cover by Vince in 1st day

Computation:

Assume;

Vince walked in 1st day = a

So,

a + (3/4)a + (3/4)(3/4)a = 83.25

a + (3/4)a + (9/16)a = 83.25

a + 0.75a + 0.5625a = 83.25

2.3125a = 83.25

a = 83.25 / 2.3125

a = 36

Distance cover by Vince in 1st day = 36 km

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