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The length of a rectangle is 9 cm longer than its width.Both the length and width are whole numbers .If the perimeter is at most 160 cm, find the largest possible length and width (hint p =2L+2W

Respuesta :

Answer:L= 45cm

W=35cm

Step-by-step explanation:

P = 2l + 2w

2(l+w)= 160

l+w = 80

From the question,

l = w+9

So w+9+w = 80

w = 71/2 = 35.5 = 35 since it must be a whole number

l = 80- 35= 45cm

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