A student enters the lab and conducts Part A of the Experiment. The student uses 32.00 mL of 2.202 M HCl, and adds NaOH in excess as instructed. If the ΔH of the neutralization reaction is known to be -57,320 J/mol H2O, what is the total theoretical heat released (in Joules)?

Respuesta :

Answer: 4012.4 Joules.

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

moles of [tex]HCl=Molarity\times {\text {Volume in L}}=2.202\times 0.032L=0.070moles[/tex]

As [tex]NaOH[/tex] is in excess , [tex]HCl[/tex] is the limiting reagent as will decide the amount of product formed and energy released.

Heat of neutralisation is the amount of heat released when 1 mole of an acid is completely neutralised by 1 mole of the base.

Given : [tex]\Delta H[/tex] = -57,320 J/mol

Thus if 1 mole of [tex]HCl[/tex] release = 57,320 J

0.070 moles [tex]HCl[/tex] release = [tex]\frac{57,320}{1}\times 0.070=4012.4J[/tex]

Thus the total theoretical heat released is 4012.4 Joules.