Answer:
[tex]7.39\times 10^{3}g[/tex] of acetic anhydride is needed
Explanation:
According to balanced equation, 1 mol of salicylic acid completely reacts with 1 mol of acetic anhydride
Number of moles = (mass)/(molar mass)
Molar mass of acetic anhydride = 102.09 g/mol
Molar mass of salicylic acid = 138.121 g/mol
So, [tex]1.00\times 10^{4}g[/tex] of salicylic acid = [tex]\frac{1.00\times 10^{4}}{138.121}moles[/tex] of salicylic acid
Hence, [tex]\frac{1.00\times 10^{4}}{138.121}moles[/tex] of salicylic acid reacts completely with [tex]\frac{1.00\times 10^{4}}{138.121}moles[/tex] of acetic anhydride.
So, mass of acetic anhydride needed = [tex]\frac{1.00\times 10^{4}}{138.121}\times 102.09g[/tex] = [tex]7.39\times 10^{3}g[/tex]