Answer:
[tex]\theta' = 13.25 rad[/tex]
Explanation:
Angular displacement of the the path of the bicycle is given as
[tex]\theta = 0.69 Rad[/tex]
also we know that radius of the path is given as
[tex]R = 13.44 m[/tex]
now we know that distance moved by the bicycle is given as
[tex]d = R\theta[/tex]
[tex]d = 13.44 \times 0.69[/tex]
[tex]d = 9.27 m[/tex]
now if the radius of the bicycle is given as
[tex]r = 0.7 m[/tex]
so the given distance is moved by the same wheel as
[tex]d = r\theta'[/tex]
[tex]9.27 = 0.7(\theta')[/tex]
[tex]\theta' = 13.25 rad[/tex]