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A girl tosses a stone into the air with an initial upward velocity of 8.00 meters/second8.00 meters/second and hears the splash when it hits the water 4.20 seconds4.20 seconds later.How deep is the water level in the well below where she tossed the stone

Respuesta :

Answer:

Depth of well = 52.92 m

Explanation:

Consider the equation of motion s = ut + 0.5 at²

Take upward direction as positive,

            Initial velocity, u =   8 m/s

            Acceleration, a =   -9.81 m/s²

            Time, t = 4.20 s

Substituting

         s = ut + 0.5 at²

         s = 8 x 4.20 + 0.5 (-9.81) x 4.20²

         s = -52.92 m

So stone travels 52.92 m below the initial position.

Depth of well = 52.92 m

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