Ethanol is produced industrially by the acid catalyzed reaction of ethylene with water. The balanced equation for this reaction is:C2H4(g) H2O(g) → C2H5OH(l)If water is present in excess, how many grams of ethanol can be produced from 42.7 g of ethylene?

Respuesta :

Answer:

70.15 g

Explanation:

The balanced reaction is

C₂H₄(g) + H₂O(g) → C₂H₅OH(l)

The molar mass of ethylene is:

2*12 g/mol of C + 4*1 g/mol of H = 28 g/mol

And the molar mass of ethanol is:

2*12 g/mol of C + 6*1 g/mol of H + 1*16 g/mol of O = 46 g/mol

For the reaction, the stoichiometry is 1 of ethylene for 1 mol of ethanol, that means that:

28 g of Câ‚‚Hâ‚„ ---------------- 46 g of Câ‚‚Hâ‚…OH

Thus, the mass of ethanol (m) is the mass of the relationship multiplied by the actual mass of ethylene, divided by the mass of ethylene of the relationship:

m = (46*42.7)/28

m = 70.15 g