Answer:
70.15 g
Explanation:
The balanced reaction is
C₂H₄(g) + H₂O(g) → C₂H₅OH(l)
The molar mass of ethylene is:
2*12 g/mol of C + 4*1 g/mol of H = 28 g/mol
And the molar mass of ethanol is:
2*12 g/mol of C + 6*1 g/mol of H + 1*16 g/mol of O = 46 g/mol
For the reaction, the stoichiometry is 1 of ethylene for 1 mol of ethanol, that means that:
28 g of Câ‚‚Hâ‚„ ---------------- 46 g of Câ‚‚Hâ‚…OH
Thus, the mass of ethanol (m) is the mass of the relationship multiplied by the actual mass of ethylene, divided by the mass of ethylene of the relationship:
m = (46*42.7)/28
m = 70.15 g